JavaScriptの単語の配列に基づいて、文内の特定の単語のすべての出現を置き換えます

文字列と文字列の配列を受け取るJavaScript関数を作成する必要があります。

関数は新しい文字列を返す必要があります。この場合、配列に存在する文字列内の単語の出現はすべて空白に置き換えられます。

この問題を解決するには、関数でString.prototype.replace（）メソッドを使用する必要があります。

例

このためのコードは-

var excludeWords = ["A", "ABOUT", "ABOVE", "ACROSS", "ALL", "ALONG", "AM",
"AN", "AND", "ANY", "ASK", "AT", "AWAY", "CAN", "DID", "DIDN'T", "DO",
"DON'T", "FOR", "FROM", "HAD", "HAS", "HER", "HIS", "IN", "INTO", "IS",
"IT", "NONE", "NOT", "OF", "ON", "One", "OUT", "SO", "SOME", "THAT",
"THE", "THEIR", "THERE", "THEY", "THESE", "THIS", "TO", "TWIT", "WAS",
"WERE", "WEREN'T", "WHICH", "WILL", "WITH", "WHAT", "WHEN", "WHY"];
var sentence = "The first solution does not work for any UTF-8 alphaben. I
have managed to create function which do not use RegExp and use good UTF-8
support in JavaScript engine. The idea is simple if symbol is equal in
uppercase and lowercase it is special character. The only exception is
made for whitespace.";
const removeExcludedWords = (str, words) => {
   let sentence = '';
   const regex = new RegExp(`\\b(${words.join('|')})\\b`, 'gi');
   sentence = str.replace(regex, "");
   return sentence;
};
console.log(removeExcludedWords(sentence, excludeWords));

出力

コンソールの出力-

first solution does work UTF-8 alphaben. I have managed create
function use RegExp use good UTF-8 support JavaScript
engine. idea simple if symbol equal uppercase lowercase special
character. only exception made whitespace.