数の奇数因子の合計を見つけるためのC++プログラム

START
Step 1-> Declare function to calculate sum of odd factors
   int sum(int num)
   declare int res = 1
   Loop While(num % 2 == 0)
      set num = num / 2
   End
   Loop For int i = 3 and i <= sqrt(num) and i++
      declare int count = 0 and total = 1
      declare int temp = 1
      Loop while (num % i == 0)
         count++
         set num = num / i
         set temp *= i
         set total += temp
      End
      set res = res*total
   End
   IF (num >= 2)
      set res *= (1 + num)
   End
   return res
Step 2-> In main()
   Declare int num = 20
   call sum(num)
STOP

例

#include <bits/stdc++.h>
using namespace std;
//calculate sum of odd factors
int sum(int num) {
   int res = 1;
   while (num % 2 == 0)
   num = num / 2;
   for (int i = 3; i <= sqrt(num); i++) {
      int count = 0, total = 1 ;
      int temp = 1;
      while (num % i == 0) {
         count++;
         num = num / i;
         temp *= i;
         total += temp;
      }
      res = res*total;
   }
   if (num >= 2)
   res *= (1 + num);
   return res;
}
int main() {
   int num = 20;
   cout<<"sum of odd factors is : ";
   cout <<sum(num);
   return 0;
}

出力

sum of odd factors is : 6