Cプログラムで再帰を使用したバイナリからグレイコード

Step 1 : Do with input n :
   Step 1.1 : if n = 0, gray = 0 ;
   Step 1.2 : if the last two bits are opposite,
      gray = 1 + 10*(go to step 1 passing n/10).
   Step 1.3 : if the last two bits are same,
      gray = 10*(go to step 1 passing n/10).
Step 2 : Print gray.
Step 3 : EXIT.

例

#include <iostream>
using namespace std;
int binaryGrayConversion(int n) {
   if (!n)
      return 0;
   int a = n % 10;
   int b = (n / 10) % 10;
   if ((a && !b) || (!a && b))
      return (1 + 10 * binaryGrayConversion(n / 10));
   return (10 * binaryGrayConversion(n / 10));
}
int main() {
   int binary_number = 100110001;
   cout<<"The binary number is "<<binary_number<<endl;
   cout<<"The gray code conversion is "<<binaryGrayConversion(binary_number);
   return 0;
}

出力

The binary number is 100110001
The gray code conversion is 110101001