C++でModifiedKnightが到達できるすべての可能な位置をカウントします

このチュートリアルでは、ModifiedKnightが到達できる可能性のあるポジションの数を見つけるためのプログラムについて説明します。

このために、8*8のチェス盤が提供されます。私たちのタスクは、ModifiedKnightが指定されたステップ数でキャプチャできるポジションの数を見つけることです。

例

#include <bits/stdc++.h>
using namespace std;
//finding the positions
void findSteps(int current_row, int current_column,int curr, int board_size, int steps,int* visited){
   //bound checking
   if (current_row >= board_size || current_row < 0
      || current_column >= board_size || current_column < 0
      || curr > steps) {
      return;
   }
   if (curr == steps) {
      *((visited + (current_row)*board_size) + current_column) = 1;
      return;
   }
   findSteps(current_row - 2, current_column - 1,curr + 1, board_size, steps, visited);
   findSteps(current_row - 2, current_column + 1,curr + 1, board_size, steps, visited);
   findSteps(current_row - 1, current_column - 2,curr + 1, board_size, steps, visited);
   findSteps(current_row - 1, current_column - 1,curr + 1, board_size, steps, visited);
   findSteps(current_row - 1, current_column + 1,curr + 1, board_size, steps, visited);
   findSteps(current_row - 1, current_column + 2,curr + 1, board_size, steps, visited);
   findSteps(current_row + 1, current_column - 2,curr + 1, board_size, steps, visited);
   findSteps(current_row + 1, current_column - 1,curr + 1, board_size, steps, visited);
   findSteps(current_row + 1, current_column + 1,curr + 1, board_size, steps, visited);
   findSteps(current_row + 1, current_column + 2,curr + 1, board_size, steps, visited);
   findSteps(current_row + 2, current_column - 1,curr + 1, board_size, steps, visited);
   findSteps(current_row + 2, current_column + 1,curr + 1, board_size, steps, visited);
   return;
}
int countSteps(int current_row, int current_column,int board_size, int steps){
   int visited[board_size][board_size];
   for (int i = 0; i < board_size; i++) {
      for (int j = 0; j < board_size; j++) {
         visited[i][j] = 0;
      }
   }
   int answer = 0;
   findSteps(current_row, current_column, 0,board_size, steps, (int*)visited);
   for (int i = 0; i < board_size; i++) {
      for (int j = 0; j < board_size; j++) {
         if (visited[i][j] == 1) {
            answer++;
         }
      }
   }
   return answer;
}
int main(){
   int board_size = 8, steps = 1;
   int current_row = 4, current_column = 4;
   cout << countSteps(current_row, current_column,board_size, steps);
   return 0;
}

出力

12