C＃でLINQおよびLambdaとの結合を利用するにはどうすればよいですか？

内部結合は、両方のテーブルに一致するか、両方のテーブルに存在するレコードまたは行のみを返します。以下に示すように、条件に基づいて複数のテーブルへの結合を申請することもできます。複数の条件での結合を申請する必要がある場合は、匿名タイプを使用してください。

以下の例では、LinqHereに参加するために使用できる2つの方法を記述しました。部門と従業員が参加します

例

class Program{
   static void Main(string[] args){
      var result =
      Employee.GetAllEmployees().Join(Department.GetAllDepartments(),
      e => e.DepartmentID,
      d => d.ID, (employee, department) => new{
         EmployeeName = employee.Name,
         DepartmentName = department.Name
      });
      foreach (var employee in result){
         Console.WriteLine(employee.EmployeeName + "\t" +
         employee.DepartmentName);
      }
      var result1 = from e in Employee.GetAllEmployees()
      join d in Department.GetAllDepartments()
      on e.DepartmentID equals d.ID
      select new{
         EmployeeName = e.Name,
         DepartmentName = d.Name
      };
      foreach (var employee in result1){
         Console.WriteLine(employee.EmployeeName + "\t" +
         employee.DepartmentName);
      }
      Console.ReadLine();
   }
}
public class Employee{
   public int ID { get; set; }
   public string Name { get; set; }
   public int DepartmentID { get; set; }
   public static List<Employee> GetAllEmployees(){
      return new List<Employee>(){
         new Employee { ID = 1, Name = "A", DepartmentID = 1 },
         new Employee { ID = 2, Name = "B", DepartmentID = 2 },
         new Employee { ID = 3, Name = "B", DepartmentID = 1 },
         new Employee { ID = 4, Name = "V", DepartmentID = 1 },
         new Employee { ID = 5, Name = "F", DepartmentID = 2 },
         new Employee { ID = 6, Name = "R", DepartmentID = 2 },
         new Employee { ID = 7, Name = "TT", DepartmentID = 1 },
         new Employee { ID = 8, Name = "YY", DepartmentID = 1 },
         new Employee { ID = 9, Name = "WW", DepartmentID = 2 },
         new Employee { ID = 10, Name = "QQ"}
      };
   }
}
public class Department{
   public int ID { get; set; }
   public string Name { get; set; }
   public static List<Department> GetAllDepartments(){
      return new List<Department>(){
         new Department { ID = 1, Name = "IT"},
         new Department { ID = 2, Name = "HR"},
         new Department { ID = 3, Name = "Contract"},
      };
   }
}

出力

A IT
B HR
B IT
V IT
F HR
R HR
TT IT
YY IT
WW HR
A IT
B HR
B IT
V IT
F HR
R HR
TT IT
YY IT
WW HR