指定された文字を使用して可能な単語を印刷するPythonプログラム

このチュートリアルでは、指定された文字で可能なすべての単語を検索します。理解を深めるために、いくつかのテストケースを見てみましょう。

Input:
words = ["hi", "hello", "bye", "good"]
characters = ["h", "i", "b", "y", "e"]
Output:
hi
bye

以下の手順に従って、目標を達成しましょう。

アルゴリズム

1. Initialize the words and characters list.
2. Write a function which returns a dictionary containing a count of each char of the word.
   2.1. Initialise an empty dictionary.
   2.2. Iterate through the word, and increment char count by one if already present else initialise it with one.
   2.3. After the loop return dictionary.
3. Iterate through the words list.
   3.1. Initialise a variable flag with 1.
   3.2. Find char count with the help of above function and store it in a variable.
   3.3. Iterate through the above-returned dictionary.
      3.3.1. Check whether the key is in the characters or not.
         3.3.1.1. If not present, make the flag to zero.
      3.3.2 Else check for the equality count of character in characters and dictionary.
         3.3.2.1. If not equal, make a flag to zero.
3.4. If the flag is equal to one.
   3.4.1. Print the word.

上記のアルゴリズムを実装しましょう。

例

## initializing the lists
words = ["hi", "hello", "bye", "good"]
characters = ["h", "i", "b", "y", "e"]
## function which returns dictionary containing char counts
def char_count(word):
   ## initializing an empty dictionary
   char_count = {}
   ## loop to find the frequency of the chars
   for char in word:
      ## incrementing the char count by one
      char_count[char] = char_count.get(char, 0) + 1
   ## returning dictionary
   return char_count
## iterating through the words list
for word in words:
   ## initializing flag to one
   flag = 1
   ## getting the char count using char_count() function
   chars = char_count(word)
   ## iterating through the chars
   for key in chars:
      ## checking for the presence of key in the characters
      if key not in characters:
         ## updating the flag value to zero
         flag = 0
      else:
         ## comparing the count of chars in chars and characters
         if characters.count(key) != chars[key]:
            ## updating the flag value to zero
            flag = 0
      ## checking the flag value
      if flag == 1:
         print(word)

出力

上記のプログラムを実行すると、次の結果が得られます。

hi
bye

結論

チュートリアルについて疑問がある場合は、コメントセクションにその旨を記載してください。