WHERE句を持つMySQLINTERSECTクエリをどのようにシミュレートできますか？

この例では、Student_detailとStudent_infoという2つのテーブルがあり、次のデータがあります-

mysql> Select * from Student_detail;
+-----------+---------+------------+------------+
| studentid | Name    | Address    | Subject    |
+-----------+---------+------------+------------+
|       101 | YashPal | Amritsar   | History    |
|       105 | Gaurav  | Chandigarh | Literature |
|       130 | Ram     | Jhansi     | Computers  |
|       132 | Shyam   | Chandigarh | Economics  |
|       133 | Mohan   | Delhi      | Computers  |
|       150 | Rajesh  | Jaipur     | Yoga       |
|       160 | Pradeep | Kochi      | Hindi      |
+-----------+---------+------------+------------+
7 rows in set (0.00 sec)

mysql> Select * from Student_info;
+-----------+-----------+------------+-------------+
| studentid | Name      | Address    | Subject     |
+-----------+-----------+------------+-------------+
|       101 | YashPal   | Amritsar   | History     |
|       105 | Gaurav    | Chandigarh | Literature  |
|       130 | Ram       | Jhansi     | Computers   |
|       132 | Shyam     | Chandigarh | Economics   |
|       133 | Mohan     | Delhi      | Computers   |
|       165 | Abhimanyu | Calcutta   | Electronics |
+-----------+-----------+------------+-------------+
6 rows in set (0.00 sec)

これで、WHERE句を指定したIN演算子を使用した次のクエリは、INTERSECTをシミュレートして、両方のテーブルに存在する130より大きいすべての「studentid」値を返します-

mysql> Select Student_detail.studentid FROM Student_detail WHERE student_detail.studentid >130 AND student_detail.studentid IN(SELECT Student_info.studentid FROM Student_info WHERE Student_detail.studentid > 0);
+-----------+
| studentid |
+-----------+
|       132 |
|       133 |
+-----------+
2 rows in set (0.00 sec)