switchcaseを使用してライブラリ管理システムのCプログラムを作成する

問題

Cプログラミングを使用して図書館の本関連情報を保存する方法。

アルゴリズム

Step 1: Declare a structure which holds data members
Step 2: declare variables which are used for loop
Step 3: use switch case to work on each module
Step 4: case 1- for Adding book information
        Case 2- for Display book information
        Case 3- for Finding number for books in library
        Case 4- for EXIT

プログラム

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
#include<string.h>
struct library{
   char bookname[50];
   char author[50];
   int noofpages;
   float price;
};
int main(){
   struct library lib[100];
   char bookname[30];
   int i,j, keepcount;
   i=j=keepcount = 0;
   while(j!=6){
      printf("\n1. Add book information\n");
      printf("2.Display book information\n");
      printf("3. no of books in the library\n");
      printf("4. Exit");
      printf ("\n\nEnter one of the above : ");
      scanf("%d",&j);
      switch (j){
         /* Add book */
         case 1:
            printf ("Enter book name = ");
            scanf ("%s",lib[i].bookname);
            printf ("Enter author name = ");
            scanf ("%s",lib[i].author);
            printf ("Enter pages = ");
            scanf ("%d",&lib[i].noofpages);
            printf ("Enter price = ");
            scanf ("%f",&lib[i].price);
            keepcount++;
            i++;
            break;
         case 2:
            printf("you have entered the following information\n");
            for(i=0; i<keepcount; i++){
               printf ("book name = %s\n",lib[i].bookname);
               printf ("\t author name = %s\n",lib[i].author);
               printf ("\t pages = %d\n",lib[i].noofpages);
               printf ("\t price = %f\n",lib[i].price);
            }
            break;
         case 3:
            printf("\n No of books in library : %d", keepcount);
            break;
         case 4:
            exit (0);
      }
   }
   return 0;
}

出力

1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 1
Enter book name = HarryPotter
Enter author name = hp
Enter pages = 250
Enter price = 350.6

1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 2
you have entered the following information
book name = HarryPotter
         author name = hp
         pages = 250
         price = 350.600006

1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 3

No of books in library : 1
1. Add book information
2.Display book information
3. no of books in the library
4. Exit

Enter one of the above : 4